Again, wrong formula. Again, FEers ignore that Lake Ontario, the CN Tower, and the target object are not on the surface of the hypothetical sphere. They have altitude more than their height. Do you really think that Lake Ontario is at sea level? Please do try harder. Why do you believe that you can't see beyond the drop? Do you think the photons get too tired to travel over Lake Ontario? Please think.

I know you can't do your own maths Gulliver, so I did them for you! I adjusted the post to reflect your concerns about sea level. Here's a synopsis.

**Given Values**Height of the observation deck: 1,135 feet

Generous height of eye level: 6 feet

Elevation of Toronto: 249 feet

Mean Radius of the Earth at sea level (lol) = 20,903,520 feet

h = Height of observation deck + Generous height of eye level + Elevation of Toronto

R = Mean radius of the Earth (lol)

h= 1390 feet

R= 20,903,520 feet

**Formula**How far you can see if you were on a sphere = R*ACOS(R/(R+h))

How far you can see if you were on a sphere = 20925524.9*ACOS(20925524.9/(20925524.9+1390))

How far you can see if you were on a sphere = 241,057.18 feet

How far you can see if you were on a sphere = 45.65 miles

Looks like you got yourself a few more miles! Still, you have over 54 more miles to account for, but as I know you'll not do any of your own math and just tell us to try harder, I guess we'll just have to leave it as it.

Flat-Earth victory!