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**Flat Earth Theory / An inconvenient hemiplane.**

« **on:**December 01, 2020, 06:46:35 PM »

Assuming the distance from the North Pole (NP) to the Equator (E) is 10,000 km whether speaking of FE or RE, and that the Equator to the southern edge (or South Pole) is an additional 10,000 km, we can easily calculate the area of each hemiplane using A = pi*r squared.

Where r = 10,000 km from NP to E, the area of the northern hemiplane = 314,159,265 kmsq.

Where r = 20,000 km from NP to SP (or southern edge) the area of the world = 1,256,637,061 kmsq (which, btw, is about 2.46 times the area in RE theory).

To calculate the size of the southern hemiplane, simply subtract the northern hemiplane from the total, which = 942,477,796 kmsq.

Therefore, the southern hemiplane is exactly 3 times the size of the northern hemiplane.

Does that agree with FE theory?