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Flat Earth Theory / Gravity/Accelerating earth plane - Different accelerations? - And more questions
« on: September 20, 2018, 03:16:23 PM »
So i got a couple questions for you, after i have read a lot of your wiki but there is some things i would like to have further explained, before i can subscribe to this theory.
Here i am referring to this:
https://wiki.tfes.org/Frequently_Asked_Questions#Why_doesn.27t_gravity_pull_the_earth_into_a_spherical_shape.3F
In the FAQ you just say that the sun acts as a spotlight but no explanation is made to how this works.
Found here:
https://wiki.tfes.org/Frequently_Asked_Questions#How_do_you_explain_day.2Fnight_cycles_and_seasons.3F
Source: http://physicstasks.eu/929/centrifugal-force-on-the-equator
And i am here referring to the second last paragraph in here:
https://wiki.tfes.org/Occam%27s_Razor
https://www.youtube.com/watch?v=QvTmdIhYnes
I know it's possible to simulate zero-gravity, using an airplane flying towards the ground so you're free falling, or the equivalent to free falling if we imagine we are on a flat plane which is accelerating towards us. But this is only done for short periods of time, for about 20-30 seconds. It is probably possible to do this for longer, but definitely not for 50 minutes like this video is.
Source: https://www.youtube.com/watch?v=FEWy6jyBLfM
I have actually calculated how far up you would need to be using the equation of motion for objects moving in 1D with a constant acceleration. Since motion in the different planes is independent of eachother, i only need to calculate the motion in the y-direction (up and down).
d=1/2*a*t2+v0*t+s0
Where d is the distance traveled, a is the acceleration, t is time, v0 is the starting speed and s0 is the starting position. Every unit used is SI-units.
We can just remove the last two parts because the starting speed is 0 and so is the starting position.
d=1/2*9.8 m/s2*((50*60) s)2=44000 km. Space is defined to start at 100 km. You have estimated the sun to be from 1100 km away to 4800 km away.
Source for sun distance: https://wiki.tfes.org/Distance_to_the_Sun
Anyway you would have to be atleast 9 times as far away from Earth as you claim the sun is and deep into space (Which you claim we have never been), if you were to fake this video with a zero-gravity plane.
Where it says space travel is faked: https://wiki.tfes.org/The_Conspiracy#Motive_of_the_Conspiracy
[/list]
I know that was a lot of questions, but thanks for reading! I am looking forward to hearing your answers.
- Gravity/accelerating earth plane
Here i am referring to this:
https://wiki.tfes.org/Frequently_Asked_Questions#Why_doesn.27t_gravity_pull_the_earth_into_a_spherical_shape.3F
- Day and night
In the FAQ you just say that the sun acts as a spotlight but no explanation is made to how this works.
Found here:
https://wiki.tfes.org/Frequently_Asked_Questions#How_do_you_explain_day.2Fnight_cycles_and_seasons.3F
- Occams razor - Centripetal acceleration
Source: http://physicstasks.eu/929/centrifugal-force-on-the-equator
And i am here referring to the second last paragraph in here:
https://wiki.tfes.org/Occam%27s_Razor
- Videos from ISS
https://www.youtube.com/watch?v=QvTmdIhYnes
I know it's possible to simulate zero-gravity, using an airplane flying towards the ground so you're free falling, or the equivalent to free falling if we imagine we are on a flat plane which is accelerating towards us. But this is only done for short periods of time, for about 20-30 seconds. It is probably possible to do this for longer, but definitely not for 50 minutes like this video is.
Source: https://www.youtube.com/watch?v=FEWy6jyBLfM
I have actually calculated how far up you would need to be using the equation of motion for objects moving in 1D with a constant acceleration. Since motion in the different planes is independent of eachother, i only need to calculate the motion in the y-direction (up and down).
d=1/2*a*t2+v0*t+s0
Where d is the distance traveled, a is the acceleration, t is time, v0 is the starting speed and s0 is the starting position. Every unit used is SI-units.
We can just remove the last two parts because the starting speed is 0 and so is the starting position.
d=1/2*9.8 m/s2*((50*60) s)2=44000 km. Space is defined to start at 100 km. You have estimated the sun to be from 1100 km away to 4800 km away.
Source for sun distance: https://wiki.tfes.org/Distance_to_the_Sun
Anyway you would have to be atleast 9 times as far away from Earth as you claim the sun is and deep into space (Which you claim we have never been), if you were to fake this video with a zero-gravity plane.
Where it says space travel is faked: https://wiki.tfes.org/The_Conspiracy#Motive_of_the_Conspiracy
[/list]
I know that was a lot of questions, but thanks for reading! I am looking forward to hearing your answers.