This applies to measuring systems that are constant.

The dollar is divided by dimes and pennies, so it will work.

The mile is divided by foot and by inches, so it will work.

British currency isn't based on constants like that.

Ah, so if it doesn't support your arbitrary hypothesis, we can just toss it out. Got it.

I guess we're also going to ignore how none of your answers are 'right' in so far as actually describing any sort of unit then, as I also pointed out? That they're just largely meaningless numbers?

Or maybe we should discuss the fact that the reason for your dismissal of British currency applies equally to rotational duration and orbital duration?

The rotational and orbital duration should have constant ratios. It is not merely arbitrary that the number of hours in a day should fit into the number of days in a year.

This applies to measuring systems that are constant.

The dollar is divided by dimes and pennies, so it will work.

The mile is divided by foot and by inches, so it will work.

British currency values are not based on constants like that.

The pound was divided by shillings and pennies, in the same way that your dollar is divided by dimes and cents/pennies.

However;

1 Dollar = 4 Quarters

1 Quarter = 25 Cents

So .... 4/25 = ... what?

As I described earlier, the first number needs to be the larger one and the greatest hierarchical unit in the scenario.

Can someone give me a TLDR of the thread? I'm really not getting the argument that Tom is trying to make.

TL;DR (I think) Because the number of hours in a day don't go neatly into the number of days in a year, the RE model can't be correct.

If I've erred, a correction would be greatly appreciated however.

tom's argument (correct me if i'm wrong, tom) is that there must be an integer number of rotations in a single orbital period.

i still don't understand where he's getting that from.

I *think* it has to do with solar noon year to year. He doesn't seem to get that solar noon on important days (like the equinoxes) don't happen at the same time on the calendar every year. That, in fact, the only reason they even stay close is because of adjustments such as leap year.

The Solar Year says that the sun should be in the same place in the sky after 1 Solar Year.

A visualization.

The sun travels across the earth's surface each day.

Earth circumference = 24,901 mi. In 1 Day the sun travels over 24,901 mi. of earth.

24,901 / 24 = 1037.54166667 miles. Over 1 hour the sun travels over 1037.54166667 miles

After 365 days: 24,901 mi. x 365 days = 9088865 miles

After 365.24 days: 24901 x 365.24 = 9094841.24 miles

Difference = 5976.24 miles

5976.24 miles / 1037.54166667 miles = 5.76. The hours in miles fits into the difference by 5.76 times. Where are those extra hours coming from? The sun will not be in the same place.