I think you underestimate how big the pyramids are. Regardless, I did the math, why don't you? No need for conjecture at this point.
sure. I am, of course, assuming the earth is a perfect sphere and not oblate with varying bumps.
because a^2 +b^2 = c^2 with a being the 755.9 ft span of the pyramid in question(Giza) and b being the radius of the earth spanning 20,925,524.9 feet.
a^2 = 57384.1 feet
b^2 = 437,877,592,340,520.01 feet
a^2+b^2= c^2 = 437877592397904.11 feet
c= the square root of 437877592397904.11= 20925524.90137
c-a= the drop due to the curvature of the earth = 0.00137 feet.
this equates to .418 mm in drop. The smallest items visible to the naked eye are between .1-.3mm in size, so the ability to notice a .4mm drop across 755.9 feet is close to impossible to notice without a tool. this distance would not affect the construction of a building.
if i did anything wrong let me know. seriously.