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Flat Earth Theory / Re: International Space Station
« on: June 16, 2019, 10:07:35 AM »
Thanks for resurrecting my question, Cactus1549
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In fact, that brings up a question I would like FE to explain:There is no "need" for the world to be the way it is - it just happens to be.
The original question should be not why does the north pole "need" to be in the centre - as you say, it doesn't need to be, it just happens to be. Like the UK doesn't need to be separated from Europe by water, it just happens to be (although hasn't always been). A better question is why do you believe that the north pole is at the centre of the flat earth. And I'd suggest the answer to that is because Rowbotham lived in the northern hemisphere. From that vantage point one can observe Polaris stationary (more or less) above the North Pole and other stars rotating around that point. So it makes sense, if you're going to create a FE model, to make that the centre. But if you're in the Southern hemisphere you'd see stars rotating in the opposite direction around some southern point.
http://www.sacred-texts.com/earth/za/za24.htmHe claims to have "proven" that the earth does not move, starting on page 63 of Earth Noy A Globe, where he talks about the movement of a ball thrown up vertically from a moving ship. According to SBR and the drawing on page 65, the ball retains the horizontal movement of the ship until it reaches its highest point, and then it falls back down vertically. That reminds me of what happens to cartoon characters who run off a cliff: they keep moving horizontally until the horizontal movement "expends itself", and then they plummet vertically. For those who had any doubt, Mythbusters proved convincingly that gravitational and horizontal movement of a bullet are completely unrelated:
Not for the first time, SBR opens his description with a non-valid statement by sayingQuoteAs the earth has been proved to be fixed, the motion of the sun is a visible reality
The shape of the Sun could not possibly be spherical.And just how does the ether/orgone energy alter the apparent shape the sun to make it look circular, regardless of where or when you are standing? I suppose that also depends on this question: what is the real shape of the sun, apart from "not spherical"? I also note that the PDF you linked (Galaev.pdf) does not even contain the word "orgone"..
The reason it appears circular when viewed from distance is the existence of a different index of refraction of ether for each latitude.
The ether is latitude dependent.
http://www.orgonelab.org/miller.htm
"The measurements were latitude-dependent as well."
http://www.orgonelab.org/EtherDrift/Galaev.pdf
On page 218, a formula for the latitude dependent ether drift.
The CORIOLIS EFFECT formula used by Michelson and Gale is also latitude dependent (ether drift formula).
The existence of the ether shows that there are latitude dependent indexes of refraction.
This changes everything.
In the interest of providing some possibilities I will give an option for the flat Earth.That's the difference between FE and RE. In RE, we can calculate where those rockets are going, and why they stay up there. RE can even tell us why GSO works the way it does. The same goes for the sun and moon. In FE, all you can do is to say that "they float up there". What keeps them there, angels perhaps? And I assume that, as angels are supernatural, we can't calculate what they'll do next. Does that mean that RE theory has figured out what makes angels tick?
What if, when rockets are shot up into the with satellites to go into orbit, they go up just as the rocket scientists think they do, but inside of going into an orbit around the globe shaped Earth, they fall into a circling overhead type path. This would be in the same sort of pattern that the sun and moon apparently travel in. If the sun and moon could do it, so could a satellite. Right?
I can't really think of how this would work in Geostationary Orbit. Maybe someone else can come up with that one.
If you read Rowbotham's "Earth not a globe!", he seems to think that the vanishing point is somehow defined by the optical resolution: once the distant object gets small enough that the eye can no longer resolve it, that object is at the vanishing point, according to him. Hence smaller objects reach the vanishing point before larger ones. Which is no more than obfuscation or, in plainer terms, bullshit. Unfortunately FEers seem to accept Rowbotham as gospel.Why the eye closer to the table couldn't see wider portion of the table?Perhaps I can help you there. Tom is talking about the resolution of the human eye. It's often ballparked at around 1/60th of a degree. Biological vision is a lot more complex than a digital camera, but the same principles apply. There's a certain "resolution" to it. Like a pixel in a camera. If 2 rays of light land on the same "pixel," they cannot be separated visually.
What would limit the sight to the narrower band?
If you are looking along a surface, all the points of that surface merge into a single line... in the extreme, they merge to a single pixel. But as you rise up and look down on the surface, the angle between the points gets larger, and the rays of light from them land on different "pixels" in your eye/camera.
That all makes sense right?
I wonder what you consider the cellular towers every couple miles to be? GPS is not from sats, no no its from ground based positioning for the most part. Balloons and aircraft contribute. Don't be swallowed by fiction, embrace facts.I live in Australia. Once you are away from the main cities and towns, there are LOTS of areas where there is zero mobile reception. Yet, GPS still works fine there. The same is true when you are on a ship in the middle of the ocean. It is clear that GPS works fine, even if there is no mobile service at all. Here's how I know this.
This seems to be related the subject. Atmospheric refraction as explained by the British Astronomical Association.The table in your link shows just how irrelevant diffraction is to my question: even with rays parallel to the earth's surface (0 degrees), the diffraction is less than 0.5 degrees. My question asks how the sun can be seen to set if it is at least 3 degrees above the horizon. Also, of course, diffraction would make us see the sun "set" even higher in the sky. According to the table, diffraction would add about 15' my minimum elevation, i.e. the setting sun never "sets" less than 3.25 degrees above the horizon.
https://britastro.org/node/17066
Sorry Reer, you are wrong, about the Sun's altitude and viewing angle.That's why I said I used measurements that gave the best possible case for FE. With other measurements, such as yours, it only gets worse; that's also why I gave the example of sunset at 45 degrees elevation. And it's hard to pin FE down on any real measurements. The 700 miles I quotes comes from their own wiki https://wiki.tfes.org/Distance_to_the_Sun.
The FE statement for the Sun is 30 km in diameter, 3000 km in altitude. I made no calculations whatsoever, but it seems FErs use this altitude because it is the only possibility to flat a sphere with a very far away Sun with parallel rays and have the same shadows based on the oblate spheroid model. Also, the diameter is purely based on apparent size of view (angular size).
Then, based on your assumption, the Sun being over the ICE wall (worst case) and the observer being also over the 180° opposite ICE wall, the rectangle triangle would have a base of 20000 km and the vertical of 3000 km, what gives a (atan(3/20)) of 8.53 degrees. This would be the lowest inclination (altitude) the Sun would appear anywhere over the FE for an observer. Anywhere the observer or the Sun moves, the altitude will increase.
The best possible analogy for what is 8.5° of altitude, is looking to your home front door from the curb across the street. A regular door is about 80 inches tall, a regular city street is about 30 ft wide plus 15 ft from the curb to the door, total 45ft = 540 inches. It would be atan(80/540) = 8.4°.
So, just walk to the curb across the street and look back to the top of your home front door, that is the lowest altitude the Sun would be anywhere over FE.
Now, thinking about apparent size. If the FE Sun right over you will have "x" view diameter, and it is 3000 km of altitude, on that viewing experience Ice wall to Ice wall, the hypotenuse will be sqr(3000²+20000²) = 20223 km, the delta size = 3000/20223 = 0.15 or 15%. Suppose the apparent Sun size right over you is around a US Quarter Coin, at that longest distance it will be the size of your shirt button. That is big enough to be completely visible and shinning bright on the sky, mostly considering that (according to FE wiki) the Sun is a globe spinning, shinning in all directions, not only as a disc spotting light down, as it was said before. Notice that according to this size and altitude, vanishing point does not make it disappear at all. It would looks like a street lamp at 150ft (50m) away.
So, where is the night sun?
Lake Pontchartrain transmission line, 15 miles, at 8" /mile² is 1800" (45.72m) down the horizon curvature.I love the way you can see the transmission line bend with the curvature of the earth. On the second photo you can clearly see that lines connecting the tops or bottoms of the poles start bending right from the beginning. Nowhere is it straight. There is nothing in FE "perspective" that can cause that bend. You must have PhotoShop'ed the photo ;-)