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Flat Earth Theory / Escape Velocity
« on: June 14, 2018, 03:55:14 PM »
Greetings,
If the escape velocity is 25,020 mph; how can anyone reach that speed without blacking out or being injured? These are the numbers I found on various websites, including nasa. 25,020 mph = 11,184.941 m/s2 = 1140 g-units. “Modern pilots can typically handle a sustained 9g (88 m/s2)". I understand certain variables exist that are not included in these simple equations. But the numbers are so far apart it seems impossible. Can someone give me some insight please?
If the escape velocity is 25,020 mph; how can anyone reach that speed without blacking out or being injured? These are the numbers I found on various websites, including nasa. 25,020 mph = 11,184.941 m/s2 = 1140 g-units. “Modern pilots can typically handle a sustained 9g (88 m/s2)". I understand certain variables exist that are not included in these simple equations. But the numbers are so far apart it seems impossible. Can someone give me some insight please?