I can't hold your hand through understanding Relativity. Clearly you aren't grasping one of the pillars of the theory, which is that in any FoR, an observer in said frame measures the same value for c. Even if that observer is accelerating with respect to another observer. And there is no law that prevents something from undergoing constant acceleration indefinitely. The hypothetical object that is constantly accelerating never exceeds c from its own frame. It is only from outside frames that relativistic effects on its observed velocity would be observed. You need to come to terms with how this all works before you start an argument that is nonsense.
I dont need HAND HOLDING
you DONT UNDERSTAND RELATIVITY
p1 E p2
if E is accelerating always toward P2
then P1 sees E moving away at a constant acceleration of 10 m/s^2
but E cant move faster than C THIS IS basic tenant of relativity .. i dont need to argue it it is
so when the E reaches the speed of C it is essentially NOT ACCELERATING
no ACCELERATION
MEANS no FORCE DOWN
just moving at C does not create a force down sorrry
the reason YOU FEEL A FORCE DOWN in an elevator is BECAUSE THERE IS gravity which UNIVERSAL acceleration is supposed to REPLACE
I HAVE ALSO SHOWN that with the equations from RELATITIVITY THAT THE FE'S USE to prove the validity of UA
that dv/dt = g (1 - v^2/c^2)^(3/2)
notice that as v approaches c that the portion under the exponent is near 0
a number near 0 to any power is a smaller number near 0
is that enough bloody HAND HOLDING FOR YOU MR DAVE THE DONKEY