Did you miss this? I’m talking about 2 separate jumps 5 minutes apart.
Indeed. However, that's inconsistent with your claim that the relative velocity between the jumper and the Earth has increased. If the jumps are separate, then the velocity at the start of each jump is 0. You know, the lack of motion.
See, the problem is that you keep contradicting yourself at every step. It's impossible for all your statements to be true, so we're left picking out the ones that were closest to plausible.
No, that’s not what I believe but according to numerous statements in the wiki, that is what the FE position is.
I am reliably informing you that it's not.
Or do I misunderstand that the FE position is that an object doesn’t “fall”, but that the earth comes up to meet it?
The two are one and the same from a physics standpoint. You cannot have one and not the other. So, yes, you are misunderstanding not only the FE position, but also the most basic physics behind
any physical model, Round Earth or Flat.
What does that object do during the time it takes for the earth to meet it (in a vacuum)?
Laymen would call it "falling".
The scenario I’ve described is conceptually the same as the bowling ball/feathers video that is in the wiki.
It emphatically is not, because regardless of which units you settle on (you still haven't answered that), your numbers are a complete mess.
“At the moment of release the feathers cease being accelerated upwards, are inert in space”. Synonyms for “inert” are “motionless”, “unmoving”, “stationary”
Yes. In other words, their velocity is not 200,000m/s, km/s, mph, or
anything. Their velocity, relative to the Earth, is 0m/s.
(is this where I am supposed to ask “motionless”, “unmoving”, “stationary” relative to what”?)
Indeed, you catch on quickly! It's a shame you didn't think to ask yourself that before you lunged into this diatribe.
I think “hover” would be an applicable synonym as well since it means to be motionless in the air.
For an infitesimally short period of time, this would be correct, but that does not make hovering and falling one and the same. Immediately
after release, the distinction between falling and hovering would become rather apparent. In one scenario, you start with a velocity of 0m/s and an acceleration of 9.81m/s^2. In the other, the initial velocity is 0m/s and the acceleration is 0m/s^2. Relative to the Earth, of course.
1) when you perform the experiment the first time on a flat earth with UA, would a clock on the bowling ball and feathers show them meeting the ground in the same amount of time as a clock that is being accelerated on the ground?
No - there would be a marginal, almost unobservable difference. The same is true for RET and gravity. Indeed, there would be no observable difference between the RET and FET scenario. This would become apparent if you used numbers that aren't nonsense.
To give you an idea, in Clyde's scenario that difference would be roughly 1s vs ~1.0000000033s. Just over three billionths of a second of a difference, rather than the three tenths you're proposing. This is why being countless degrees of magnitude is not good for you.
One also has to wonder why the bowling ball and feathers didn’t disintegrate while smashing into the atmolayer.
Because, unlike your assertion, they do not suddenly start yeeting themselves into the air at 200,000 of
some unspecified unit. They start at 0m/s relative to Earth, and accelerate until they reach terminal velocity, or until stopped by some other force. It comes down to your numbers being complete nonsense again. Fix those, and you'll start making sense of a lot of things.
2) Second question is if you perform the same experiment a second time, say 5 minutes later, would a clock on the bowling ball and feathers measure the same amount of time to meet the ground as it measured the first time?
Indeed - the two drops would be exactly the same from an earthly observer's frame of reference. You forgot to ask yourself my favourite question -
relative to what?.
Again, the answer is no because during the intervening 5 minutes, the accelerating flat earth has increased its velocity
Relative to what?
but the clock on the bowling ball and feathers is just as inert (motionless, unmoving, stationary and still hovering) for the second experiment as it was for the first.
Relative to what? And no, a bowling ball that's been dropped is not hovering, it's falling. You can test this yourself. Try dropping a bowling ball over your foot. Will you see it hover, or is your foot in imminent danger?
That means the relative velocity between the earth and the bowling ball and feathers is different for the first and second experiment
Impossible - as you just stated, in both scenarios the bowling ball starts motionless. In other words, its velocity relative to the Earth is 0m/s.
Nope, its a basic principle of GR
You have no grasp of basic classical mechanics (see above), and are in no position to even get started with GR.
I didn’t answer your question because it has nothing to do with the concept that is being discussed. How fast the jumper sees the ground approaching him is irrelevant.
Of course it's relevant. Your argument presupposes the impossible. Between that and your fast and loose approach to numbers, it renders everything you say incoherent.
Yes, if someone managed to jump off a chair and found themselves plummeting towards the Earth at near-light-speed, a lot of physics as we know it would break in exciting ways. It still wouldn't make milliseconds a unit of velocity, and it wouldn't make velocity the same as acceleration, but some things would indeed break. However, it's satisfying that very big "if" that's your current problem.
What does matter is that if jumper’s clock objectivelymeasures one second to hit the ground, then a clock on the ground will objectively measure 1.3s to hit the ground.
For this to be the case, the diver would have to be approaching the Earth at ludicrous speeds. He is not. And that's why the relative speed matters. As Clyde rightly pointed out, it is not 200,000ms. So, now you just need to actually calculate it, and then plug the results into the calculator you found online without understanding what it does. This time, with correct units.
By the way, I'm giving you a chance here. This is like your umpteenth troll account. You can drop the act, or you can join your other pricelessalts. We won't have fake RE'ers sully the reputation of what is already the losing side.