Can you show us your calculation? It could put this to rest once and for all.

Obviously he can’t. He had to use an online calculator to effectively work out the average of 2 numbers, and didn’t understand why that wasn’t appropriate for this problem.

^This is a flat out lie.

I was the first here to point out the average velocity of the rocket to an altitude of 250km in a time frame of 5 minutes, using

**d=rt**, comes out to 3,000 km/h.

I also acknowledged on numerous occasions, that

**(final velocity + initial velocity)/2** is indeed a linear calculation.

I then pointed out that an average velocity calculation derived by calculus would not help you or the rest of the RE crowd here. In fact, it would only further serve to prove your bogus flight times and velocities provided at

**t+1, t+2, etc.,** as the bs they are.

I may have made a mistake.

Nope, you just posted a lie, as the record of the thread demonstrates.

In your follow up BS iteration program, you claim it demonstrates a final altitude of nearly 10,000km!

The maximum height would be 9,831km

As a reminder, the rocket we are discussing is claimed to have achieved an altitude of only 4,500 km.

I will also point out you set g = 9.8m/s

^{2}, which is the value at sea level, not at 250km.

Initial height h0 = 250km

g0 = 9.8 (g at sea level, roughly)

In total, your contributions to this thread have been entirely worthless.

Quite simply, you need to go back to following your own advice which you offered to me a couple of pages back.