Wasn't really going to prolong this, but what the heck.

With all due respect, there's a few pretty smart people around these parts. Then there's me. I used to be pretty smart about 30 years ago, but then I realized I didn't need to be pretty smart anymore, forgot most of my smartness and proceeded to conquer my career goal of a six figure income. If two of those pretty smart people are telling you you're mistaken, you might want to take the time to listen to them and figure out what they're saying.

First of all, velocity and acceleration are two different things. Acceleration is the rate of change of velocity over time. It is a component of velocity and needs to be taken into account when figuring velocity, but they are two separate concepts entirely. Two objects can have the same rate of acceleration and have massively different velocities.

Good to know you at least understand a few of the basics.

This is the formula for constant acceleration. a=d/t^2. Acceleration equals distance over time squared.

Close. I'm going to give you the credit that this is just a typo. When you figure out what you left off let us know.

This is the formula for velocity. v=u+at, with u being initial velocity, a being acceleration and t, time. You need to know the acceleration to solve for velocity, but they are two different things

You got another one right. Good for you.

Secondly, when solving a distance over time problems, you use *velocity not acceleration*.

No. First of all, look at what you just got right. v=u+at. Acceleration is a component of velocity. If you are using velocity to solve a distance problem you must know how acceleration affects what an object's velocity is. It's why I gave you the actual calculation for distance which is: s=ut + 1/2at

^{2}Since you didn't bother to visit the site I offered I"ll quote the highlights.

This Displacement Calculator finds the distance traveled or displacement (s) of an object using its initial velocity (u), acceleration (a), and time (t) traveled. The equation used is s = ut + ½at

^{2}; it is manipulated below to show how to solve for each individual variable. The calculator can be used to solve for s, u, a or t.

Displacement Equations for these Calculations:

Displacement (s) of an object equals, velocity (u) times time (t), plus ½ times acceleration (a) times time squared (t

^{2}).

s=ut+1/2at

^{2}Where:

s = displacement

u = initial velocity

a = acceleration

t = time

Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.

Different resources use slightly different variables so you might also encounter this same equation with v

_{i} or v

_{0} representing initial velocity (u) such as in the following form:

s=v

_{i}t+1/2at

^{2}Where:

s = displacement

v

_{i} = initial velocity

a = acceleration

t = time

I asked you not to talk to Action 80 but you did it anyway. Your grade school speed/distance/time works great for constant velocity problems but some of us graduated from grade school and moved on to physics where things like acceleration and changing velocity are discussed.

So aside from the fact that you didn’t account for gravity

You do realize that gravity is just a different value of acceleration versus the tale, right?

or air resistance in your story

With the struggle you are having with the basics, there was no way in hell you'd understand the math to account for air resistance in any scenario.

nearly every thing about it was wrong because you never considered velocity.

If you actually understood how the story applies to your struggle to understand what's going on here, you'd see that I considered the zero initial velocity case (RE) as well as accounted for an initial velocity (FE) to try to help you see how things would work.