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Flat Earth Theory / Re: Moonbounce propagation time and the distance of the Moon from Earth
« on: February 08, 2022, 08:55:10 AM »
WSJT is open source software. You can inspect the source to find the government's faked timings.
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The lack of these actual non-stop-stop flights taking placeWhere's your evidence that any of these flights are not happening?
It takes light 8 minutes to get to the sun. So is a infrared thermometer faster than light?Why does it matter how far away the sun is? Light isn't going to the sun, radiation is coming from the sun.
I am unsure if gravity explains why there are variations of gravity.Gravity varies across the earth's surface due to different distance (e.g. at altitude) from the centre of mass of the earth and due to different densities of the rock.
In the RE model the earth is orbiting the sun and the moon is orbiting the earth. With all are knowledge of gravity we are unable to calculate this orbit. Mathematically it does not work. Google the three body problem.The three body problem has no analytical solution i.e. you cannot write a formula giving the positions and velocities of the objects at time t. This does not mean "Mathematically it does not work". It is not evidence that the solar system functions in a different way.
The three body problem is either impossible or virtually impossible. The problem with the round earth model is that there are more than three bodies in our solar system. There are hundreds. With the laws of gravity being unable to explain 3 of these bodies let alone 300 it's evidence that maybe the solar system functions in a different way.
From Encyclopedia Britannica:Move the body to a different gravitational field and you will get a different force. But the mass remains the same.QuoteGravitational mass is determined by the strength of the gravitational force experienced by the body when in the gravitational field g.
Gravity does change in different gravity environments, however. Thus gravitational mass will not be equal to inertial mass.You seem to be confusing gravitational mass with weight. On Jupiter an object will weigh more than it does on earth but its gravitational mass will stay the same.
A very wild and surprising coincidence, indeed, that Gravitational Mass should exactly equal Inertial Mass on Earth to the best resolution of modern physics.This equivalence is not unique to Earth.
You seem confused - the scientific definition of the equinox , which I quoted , is taken from the timeanddate website . The two instances when the earth tilt is not angled toward or away from the sun , six months apart .
And this should give ,as near as possible , equal day and night . All in any scientific dictionary and a consequence of earth orbiting the sun with a tilt of 66.6 degrees .
you can't fit equinoxes within the heliocentric model without waffle .
Unless we've figured out how to simulate a zero-gravity environment for extended period of time I think that should be pretty convincing evidence of being out of the effects of gravity/UA.
How do you suppose that long term (days or weeks) zero gravity would be simulated on such a trip?The ISS is not zero-gravity. If it was, it wouldn't be in orbit around the earth.
I brought that up to make the point that direct observations of the Earth should trump indirect evidences like the green flash.It doesn't work like that. You can't say that because you can see no curvature then you can discount all evidence of curvature. If you are promoting a scientific model for something then you need to be able to explain all evidence.
It is the burden of proof of the one who makes the positive claim that the green flash proves RE to not only supply the RE explanation but to prove that no FE explanation is possible.No it's not. If RE has an explanation for an observation then that is more weight in favour of RE. If supporters of FE can explain it, then that is weight in favour of FE.
I don't think all that many FE'ers "deny gravity", and that's with me generously assuming that you meant "gravitation".