Further proof that the flat earth cannot have sunset can be explained with further mathematics and trigonometry.

When the sun is at the observers zenith, ie the latitude and declination coincide the time of sunset will be when the sun has traversed apparently 90 degrees from the observer or 6 hours after.

Now the 90 degrees is equal to 5,400 minutes, and with my observations yesterday at latitude 15N would be 5,215 Nm or 6,000 statute miles.

This makes the mathematics really easy.

The calculated altitude of the sun above a plane horizon (which always is at eye level according to Enag) would be Tan altitude = 3,000 (hieght)/6,000, (distance) which is Tan alt=0.5 or in this case 26.6 degrees above the horizon.

No amount of refraction or horizon rising can make me believe the horizon is more than 1/4 of the way up the sky!

Before we hear vanishing points etc lets look at what the angular measurement of the sun diameter would be at that distance,

It would be 2 times tan angle = half diameter/distance.

Pythagoras would give us a straight line distance by square root of 6,000 squared plus 3,000 squared which equals 6,708 miles.

So tangent angular measure would be 14/6708 which is equal to 14.3 minutes of arc, well above what humans can see.