you have just stated that the earth literally raises. If the sun is 3000 miles high, how the heck do the photon leave at ground level? What is emitting them? Do you understand that you are saying that the sun is literally burning a hole in the ground?
EDIT: Btw, these two diagrams are mutually exclusive! In the top one the angle of the path is positive, with respect to the ground, and in the bottom one it's negative. It's a paradox!
EDIT2: if these are to scale, the tree in the top diagram is 3000 miles high
Perspective changes the orientation of bodies around you. Perspective has has oriented the man to be 90 degrees from zenith for the sun. A photon leaving the sun at 90 degrees is pointed at the man, and that is the straight line path it will take.
this is a meaningless sentence. Does the earth literally raises? Is the sun torching it at sunset?
In your model the sun is 6000 miles away and 3000 miles high. The photons cannot be emitted at ground level. There is nothing there to do it. They have to cover the vertical distance somehow.
The cases are two: either the earth literally raises, and the sun is leaving smouldering craters around the world at sunset
Or, the light bends somewhere, getting down in altitude before realigning parallel to the ground.
There is no way around it. Which is it?
Also, in your diagrams you have a paradoxical situation in which you can't conserve the orientation of the line of sight with respect to the ground. The direction is radically different. You have to address this too.
EDIT: I've read this now:
At sunset we see the sun at 90 degrees and the sun also sees us at 90 degrees. A laser pointer held by the observer or by the sun would be pointed at 90 degrees to hit the target.
So, let's go through this. Assuming a flat earth with no obstacles... a sunset in the desert.
I point a laser beam at eye level, 6' , parallel to the ground. What happens?
Basic geometry suggests that after a mile, it will still be at 6' height. The same after 100 miles. After 6000 miles, if the earth is flat and the light goes straight, it will pass at 6' height, below a sun which is 3000 miles high.
You are saying that, instead, it's going to hit the sun.
How?! Walk me through the path of that laser. Tell me how to cross that 3000 miles divide without bending the light or without incinerating the earth