Investigating FE Jupiter
« on: June 05, 2019, 09:40:56 PM »
I found some old threads about Jupiter, but the discussion just bent to teachers, astronomy, etc, not concluding the discussion in a productive way.
My wish here, investigating FE Jupiter, is related to:

1.) Size
2.) Shape
3.) Altitude from FE
4.) Visible rotation
5.) Visible satellites passing in front and back
6.) How the Sun illuminate it and project its satellites shadow over its body
7.) Movement period over FE
8.) Why it changes visible size along the years
9.) Composition based on spectrometry

I wish the discussion stay focused on the subject.


Re: Investigating FE Jupiter
« Reply #1 on: June 05, 2019, 10:04:59 PM »
Jupiter has the same diameter as that of the Sun, Moon, Black Sun, Shadow Moon. It is discoidal in shape, as are its satellites.

If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.

The RE cannot explain the basic features of Jupiter: its angular momentum and its IR anomalous radiation.

https://www.theflatearthsociety.org/forum/index.php?topic=55860.0

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Offline stack

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Re: Investigating FE Jupiter
« Reply #2 on: June 05, 2019, 10:38:42 PM »
Jupiter has the same diameter as that of the Sun, Moon, Black Sun, Shadow Moon. It is discoidal in shape, as are its satellites.

If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.

The RE cannot explain the basic features of Jupiter: its angular momentum and its IR anomalous radiation.

https://www.theflatearthsociety.org/forum/index.php?topic=55860.0

12km = 39k'. I've flown commercially at 42k' and the Sun was still well above me.

If the Sun orbits at some 12 km above the surface of the Earth, I have flown in a commercial flight above the Sun's orbital position? Yet the sun was still well above me? How does that work?


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Offline Salviati

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Re: Investigating FE Jupiter
« Reply #3 on: June 05, 2019, 10:54:14 PM »
If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.

I live exactly at the 45th parallel; in the days of the equinoxes the sun is perpendicular to the equator and at noon I see it at 45 degrees. This means that I am 12 km from the equator. But I am also halfway between the north pole and the equator, which means that I am 12 km from the north pole. So the distance north pole - equator is 24 km. Other 24 km from the equator to the outer edge lead us to the conclusion that the earth's radius is 48 km. Is the earth really so huge? I thought it was much smaller.

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Re: Investigating FE Jupiter
« Reply #4 on: June 06, 2019, 08:30:37 AM »
Jupiter has the same diameter as that of the Sun, Moon, Black Sun, Shadow Moon. It is discoidal in shape, as are its satellites.

If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.

The RE cannot explain the basic features of Jupiter: its angular momentum and its IR anomalous radiation.

https://www.theflatearthsociety.org/forum/index.php?topic=55860.0

12km = 39k'. I've flown commercially at 42k' and the Sun was still well above me.

If the Sun orbits at some 12 km above the surface of the Earth, I have flown in a commercial flight above the Sun's orbital position? Yet the sun was still well above me? How does that work?
You know, I thought you'd got your maths wrong, but you haven't. Commercial airlines do fly above 12km. How they hell do they not hit the sun?! And how come the sun is the same angular size from a plane, in day time it should be absolutely huge from a plane as you'd be pretty close to it.

Coming back to Jupter, if that is about 24km up then we're lucky no weather balloons have hit it as they go far higher than that.

Sandokhan, honestly, what kind of nonsense is this?!
Tom: "Claiming incredulity is a pretty bad argument. Calling it "insane" or "ridiculous" is not a good argument at all."

TFES Wiki Occam's Razor page, by Tom: "What's the simplest explanation; that NASA has successfully designed and invented never before seen rocket technologies from scratch which can accelerate 100 tons of matter to an escape velocity of 7 miles per second"

Macarios

Re: Investigating FE Jupiter
« Reply #5 on: June 06, 2019, 10:15:41 AM »
...
If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.
...

And what if Sun orbits at 7345 km, or 9943 km, or 12541 km?

We know that Sun travels 15 degrees per hour, measured from observer from any place, any time of a day.
If one doesn't believe that, they can go wherever they want and check it out.
Every place on Earth has clear days when Sun is visible to everyone.

Distance from North Pole to Tropic of Cancer is measured to be 7389 km.
It gives the circumference of 46 426 km, which Sun travels in 24 hours on summer solstice.
It is 1934 km per hour.
967 km in 30 min.

Distance from North Pole to Equator is 10 000km.
(At the beginning Metre was defined as 10 millionth part of the distance from North Pole through Paris to Equator.)
It gives the circumference of 62 832 km, which Sun travels in 24 hours on Equinoxes.
It is 2618 km per hour.
1309 km in 30 min.

Distance from North Pole to Tropic of Capricorn is measured to be 12 611 km.
It gives the circumference of 79 237 km, which Sun travels in 24 hours on winter solstice.
It is 3302 km per hour.
1651 km in 30 min.

For Summer Solstice:
standing at Tropic of Cancer at noon you have Sun above your head, and 30 min later Sun is 7.5 degrees and 967 km to the west.
It gives Sun's altitude of 967 / tan(7.5) = 7345 km.

For Equinox:
standing at Equator at noon you have Sun above your head, and 30 min later Sun is 7.5 degrees and 1309 km to the west.
It gives Sun's altitude of 1309 / tan(7.5) = 9943 km.

For Winter Solstice:
standing at Tropic of Capricorn at noon you have Sun above your head, and 30 min later Sun is 7.5 degrees and 1651 km to the west.
It gives Sun's altitude of 1651 / tan(7.5) = 12541 km.

You probably wanted to say 12 000 km for Sun and 25 000 km for Jupiter, but obviously those numbers aren't very useful either.
« Last Edit: June 06, 2019, 10:23:36 AM by Macarios »

Re: Investigating FE Jupiter
« Reply #6 on: June 06, 2019, 10:45:45 AM »
None of you could explain the angular momentum paradox and the IR anomalous radiation of Jupiter.

You haven't done your homework on commercial/military flights. None fly above some 9 km; commercial flights only reach 6-8 km in altitude.

Schauberger-DePalma effect: jet engine levitation

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2044376#msg2044376

Real cruising altitude of commercial aircrafts/astronomical refraction:

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2044464#msg2044464


Your numbers amount to nothing at all, since you believe the shape of the Sun is spherical.

Here are the real numbers.

SOLAR DISK: THE IMPOSSIBILITY OF A SPHERICALLY SHAPED SUN

"The atmospheric pressure of the sun, instead of being 27.47 times greater than the atmospheric pressure of the earth (as expected because of the gravitational pull of the large solar mass), is much smaller: the pressure there varies according to the layers of the atmosphere from one-tenth to one-thousandth of the barometric pressure on the earth; at the base of the reversing layer the pressure is 0.005 of the atmospheric pressure at sea level on the earth; in the sunspots, the pressure drops to one ten-thousandth of the pressure on the earth.

The pressure of light is sometimes referred to as to explain the low atmospheric pressure on the sun. At the surface of the sun, the pressure of light must be 2.75 milligrams per square centimeter; a cubic centimeter of one gram weight at the surface of the earth would weigh 27.47 grams at the surface of the sun."



Thus the attraction by the solar mass is 10,000 times greater than the repulsion of the solar light. Recourse is taken to the supposition that if the pull and the pressure are calculated for very small masses, the pressure exceeds the pull, one acting in proportion to the surface, the other in proportion to the volume. But if this is so, why is the lowest pressure of the solar atmosphere observed over the sunspots where the light pressure is least?

Because of its swift rotation, the gaseous sun should have the latitudinal axis greater than the longitudinal, but it does not have it. The sun is one million times larger than the earth, and its day is but twenty-six times longer than the terrestrial day; the swiftness of its rotation at its equator is over 125 km. per minute; at the poles, the velocity approaches zero. Yet the solar disk is not oval but round: the majority of observers even find a small excess in the longitudinal axis of the sun. The planets act in the same manner as the rotation of the sun, imposing a latitudinal pull on the luminary.

Gravitation that acts in all directions equally leaves unexplained the spherical shape of the sun. As we saw in the preceding section, the gases of the solar atmosphere are not under a strong pressure, but under a very weak one. Therefore, the computation, according to which the ellipsoidity of the sun, that is lacking, should be slight, is not correct either. Since the gases are under a very low gravitational pressure, the centrifugal force of rotation must have formed quite a flat sun.

If planets and satellites were once molten masses, as cosmological theories assume, they would not have been able to obtain a spherical form, especially those which do not rotate, as Mercury or the moon (with respect to its primary)."


The Sun exhibits a variety of phenomena that defy contemporary theoretical understanding.

Eugene N. Parker


It is not coincidence that the photosphere has the appearance, the temperature and spectrum of an electric arc; it has arc characteristics because it an electric arc, or a large number of arcs in parallel.

British physicist C. E. R. Bruce


It is likely that the problem of the dynamics of the explosions affecting the prominences will only be solved when the electrical conditions obtaining in the chromosphere and inner corona are better understood.

Italian solar astronomer Giorgio Abetti


Observations give a wealth of detail about the photosphere, chromosphere and the corona. Yet we have difficulty in matching the observations with a theory.

Solar Interior & Atmosphere, J.-C. Pecker


The modern astrophysical concept that ascribes the sun’s energy to thermonuclear reactions deep in the solar interior is contradicted by nearly every observable aspect of the sun.

Ralph E. Juergens




PRESSURE: 10-13 BAR = 0.0000000000001 BAR

The entire chromosphere will then be subjected to the full centrifugal force of rotation, as will the photosphere itself of course.

Completely unexplained by modern science.

Since the gases are under a very low gravitational pressure, the centrifugal force of rotation must have formed quite a flat sun.

NO further recourse can be made for gravity.

Gravity has already balanced out as much as was possible of the gaseous pressure, and still we are left with A VERY LOW PRESSURE.

Solar gravity has balanced out the thermal pressure.

At this point in time the sun will turn into A HUGE GAS CENTRIFUGE WITH NO OUTER CASING, running at some 1,900 m/s.

That is, the solar gases in the photosphere and cromosphere are just standing there, with no explanation by modern science whatsoever.

As if this wasn't enough, we have the huge centrifugal force factor that is exerted each and every second on the photosphere and the cromosphere.

The centrifugal force would cause the sun to collapse into a disk in no time at all.


"However, the gravity is opposed by the internal pressure of the stellar gas which normally results from heat produced by nuclear reactions. This balance between the forces of gravity and the pressure forces is called hydrostatic equilibrium, and the balance must be exact or the star will quickly respond by expanding or contracting in size. So powerful are the separate forces of gravity and pressure that should such an imbalance occur in the sun, it would be resolved within half an hour."


Then, the heliocentrists have to deal with the Nelson effect:

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg1645824#msg1645824 (the Nelson effect of all the other planets, pulling constantly on the sun's atmosphere, acting permanently, are added to the centrifugal force)

Recourse can be made to the Clayton model equation or even the Lane-Emden equation in order to show that the value for g (computed using the 10-13 bar value in the chromosphere) is much smaller than the centrifugal acceleration.

The Clayton model provides us with the g value: g = 0,0000507 m/s^2 which is much lower than the centrifugal acceleration figure:

P(r) = 2πgr2a2ρ2ce-x2/3M

where a = (31/2M/21/24πρc)1/3

a = 106,165,932.3

x = r/a

M = 1.989 x 1030 kg
central density = 1.62 x 105 kg/m3

G = gr2/m(r)

m(r) = M(r/R)3(4 - 3r/R); if r = R, then M = m(r)

Using P(700,000,000) = 1.0197 x 10-9 kg/m2 value, we get:


g = 0,0000507 m/s2


RATIO


ac/g = 0.0063/0.0000507 = 124.26


Accuracy of the Clayton model:






You are calculating distances to the Sun based on the refractive index of the atmosphere: however, the density of aether/ether increases greatly above some 9 km all the way to the first dome, and of course from the first dome to the Sun.

Here is the real deal concering this issue.



Dr. Stuart D. Bale, UC Berkeley

KORONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2057945#msg2057945

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2058259#msg2058259

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064256#msg2064256

NEWTONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064764#msg2064764

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2065771#msg2065771

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Offline Pete Svarrior

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Re: Investigating FE Jupiter
« Reply #7 on: June 06, 2019, 01:36:08 PM »
Just a heads up: throwing the word "investigate" into your thread does not make it FEI.

See https://forum.tfes.org/index.php?topic=10086.0 and https://forum.tfes.org/index.php?topic=10088.0
Read the FAQ before asking your question - chances are we already addressed it.
Follow the Flat Earth Society on Twitter and Facebook!

If we are not speculating then we must assume

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Offline TomInAustin

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Re: Investigating FE Jupiter
« Reply #8 on: June 06, 2019, 02:39:39 PM »

You haven't done your homework on commercial/military flights. None fly above some 9 km; commercial flights only reach 6-8 km in altitude.


Oh man, you are smoking something good today.  You would have us think that no commercial or military aircraft fly above 29,500 feet or 9km.  Have you ever flown commercial?  Mount Everest is 29,029 feet or 8.84 km.   
« Last Edit: June 06, 2019, 02:43:18 PM by TomInAustin »
Do you have a citation for this sweeping generalisation?

Re: Investigating FE Jupiter
« Reply #9 on: June 06, 2019, 03:14:09 PM »
Mount Everest is 29,029 feet or 8.84 km.   

It can't be.

The height of Mt. Everest has to be lower than the official estimate since the basic triangulation method does not take into account the different refractive indexes for each layer of aether and ether.

https://web.archive.org/web/20170113180348/https://medium.com/@GatotSoedarto/the-deflection-of-light-by-refraction-not-gravity-49b9bd919aba



Amateur rockets

Actually, the way this altitude is measured is the following: According to RRS member Bill Claybaugh (1996, alleged 50 mile altitude reached), "this altitude was estimated from a image of the entire Black Rock Desert taken near peak using known distances between geographic features".

How do other amateur rocket endeavours measure their claims?

Altitude verification for the rocket will be primarily based on signals from an onboard Trimble GPS receiver.

But in fact satellites orbit at a much lower altitude, and are powered by Tesla's cosmic ray device which is the source of energy for the Biefeld-Brown effect.

An altimeter actually includes an aneroid barometer which measures the atmospheric pressure (actually it measures the effect of the dextrorotatory ether waves). A radar altimeter uses radio signals. Both methods do not take into account the layers of aether which exist above 5 km in altitude which influence both the pressure reading and also the distance travelled by the radar waves.


You are faced with the very same problem that baffled Dr. Stuart D. Bale (UC Berkeley):



If you want anyone to believe you that Mount Everest measures 8.84 km, you must explain the huge temperatures in the solar corona:


KORONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2057945#msg2057945

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2058259#msg2058259

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064256#msg2064256

NEWTONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064764#msg2064764

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2065771#msg2065771

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Offline Salviati

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Re: Investigating FE Jupiter
« Reply #10 on: June 06, 2019, 03:16:52 PM »
...
If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.
...

You probably wanted to say 12 000 km for Sun and 25 000 km for Jupiter, but obviously those numbers aren't very useful either.

I assure you that sandokhan meant just 12 Km. Go to the other flat earth society site and read his posts.

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Offline TomInAustin

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Re: Investigating FE Jupiter
« Reply #11 on: June 06, 2019, 04:10:41 PM »
Mount Everest is 29,029 feet or 8.84 km.   

It can't be.

The height of Mt. Everest has to be lower than the official estimate since the basic triangulation method does not take into account the different refractive indexes for each layer of aether and ether.

Since aether and ether do not exist and can't be shown to exist the rest of your post is pure bunk.

Since GPS and aircraft have confimed the height of Everest you are on even more shaky ground.
Do you have a citation for this sweeping generalisation?

Re: Investigating FE Jupiter
« Reply #12 on: June 06, 2019, 04:31:37 PM »
But it does exist.

Multiple proofs.

GALAEV ETHER DRIFT EXPERIMENTS:

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg1722791#msg1722791

GLOBAL/GENERALIZED SAGNAC EFFECT FORMULA:

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2117351#msg2117351

ORIGINAL MAXWELL EQUATIONS FEATURING SCALAR/LONGITUDINAL WAVES (ETHER):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2168036#msg2168036

PROOF OF THE EXISTENCE OF SCALAR/LONGITUDINAL WAVES (papers published in 1903 and 1904 by E.T. Whittaker, one of the top mathematicians of the 20th century):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg1994059#msg1994059

KORONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2057945#msg2057945

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2058259#msg2058259

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064256#msg2064256

NEWTONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064764#msg2064764

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2065771#msg2065771

RUDERFER EXPERIMENT: ABSOLUTE PROOF OF THE EXISTENCE OF ETHER, the first null result in ETHER DRIFT HISTORY

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg1846721#msg1846721


Since GPS and aircraft

Amateur rockets

Actually, the way this altitude is measured is the following: According to RRS member Bill Claybaugh (1996, alleged 50 mile altitude reached), "this altitude was estimated from a image of the entire Black Rock Desert taken near peak using known distances between geographic features".

How do other amateur rocket endeavours measure their claims?

Altitude verification for the rocket will be primarily based on signals from an onboard Trimble GPS receiver.

But in fact satellites orbit at a much lower altitude, and are powered by Tesla's cosmic ray device which is the source of energy for the Biefeld-Brown effect.

An altimeter actually includes an aneroid barometer which measures the atmospheric pressure (actually it measures the effect of the dextrorotatory ether waves). A radar altimeter uses radio signals. Both methods do not take into account the layers of aether which exist above 5 km in altitude which influence both the pressure reading and also the distance travelled by the radar waves.


"...the failure of the world's physicists to find such a (satisfactory) theory, after many years of intensive research," says Dirac, "leads me to think that the aetherless basis of physical theory may have reached the end of its capabilities and to see in the Aether a new hope for the future".

Paul Dirac, the Nobel Prize winner in physics in 1933
Scientific American, The Evolution of Physicists Picture of Nature, May 1963


GPS technology was invented by Dr. Friedwardt Winterberg, in 1955, at the age of 26: proposing to put atomic clocks into artificial satellites.

But Dr. Winterberg is also one of the best proponents of the ether theory of the 20th century.


http://zfn.mpdl.mpg.de/data/Reihe_A/44/ZNA-1989-44a-1145.pdf

Substratum Interpretation of the Sagnac and the Aharonov-Bohm effect

Dr. Friedwardt Winterberg

Ph.D., Physics 1955 Max Planck Institute, Goettingen, Germany (Adv: Prof. W. Heisenberg)
1968-Present Professor of physics, University of Nevada Reno
1955-1959 Group leader theoretical physics division at nuclear research reactor in Hamburg, Germany, under President Eisenhower's "Atoms for Peace" program
Elected member International Academy of Astronautics, Paris, France.
Member of American Physical Society.
Recipient of the 1979 Hermann Oberth Gold Medal (the highest award in astronautical research given for his work on nuclear rocket propulsion).
More than 260 single author papers in refereed journals, two books, with many citations, including citations by the NY Times, Scientific American, Physics Today et al., 55 publications since 1992.

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Offline TomInAustin

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Re: Investigating FE Jupiter
« Reply #13 on: June 06, 2019, 05:09:25 PM »
But it does exist.



But in fact satellites orbit at a much lower altitude, and are powered by Tesla's cosmic ray device which is the source of energy for the Biefeld-Brown effect.



Continuing to make false claims as if they are fact is not debate.   Links to your own posts are not proof.
Do you have a citation for this sweeping generalisation?

Re: Investigating FE Jupiter
« Reply #14 on: June 06, 2019, 08:27:07 PM »
If the Sun orbits at some 12 km above the surface of the Earth, then Jupiter must orbit somewhat at a higher altitude, perhaps some 25 km, if not more.

So, one could use that good telescope from Tom Bishop and see children playing with frisbee over Jupiter, right?  He did that over the bay, and it was 48km away.

Just going to numbers, double the distance, half the visual angular size for the same size object.  If the Jupiter has the same size of Sun, and it is only double the distance, we could see Jupiter half the size of the Sun, right Sandoknan?

Numbers again, at some point in Sun's orbit, Jupiter has an angular size of 0°00'49", while the Sun is 0°5', so the real RE angular size of the Sun is 36 times bigger than Jupiter's. RE Jupiter has 1/10 of Sun's diameter.  IF they were the same size, Jupiter should be 36 times further than the Sun.    So, for Jupiter to be actually seen 36 times smaller than the Sun (just grab a telescope and measure), and to be only twice the distance to the Sun, it must be at least 18 times smaller.   So, if the Sun has only 633 meters in diameter (your previous post), than Jupiter should be 35 meters in diameter, that would fit in my back yard... Jupiter moons would be smaller than baseballs.

Resuming, your numbers don't match at all.  Review it. 


Re: Investigating FE Jupiter
« Reply #15 on: June 06, 2019, 08:38:55 PM »
Based on picture posted by Sandokhan, below, "The effect of astronomical refraction is to make a celestial body appear higher in the sky than it otherwise would"... this text constradicts the explanation why we see the Sun rise and set at the horizon on FE.   It is said that the Sun appears to set because atmospheric refraction, when in real it still 18° high, but the picture below says otherwise, so, should I think that when we see the Sun at the horizon, it is even much more under the horizon?  2+2 can't be 3 when necessary, or 5 if required, it is 4 no matter the angle you see it.  Please review your statement.


Re: Investigating FE Jupiter
« Reply #16 on: June 06, 2019, 08:42:32 PM »
Between Jupiter and the Sun there is a very dense region of aether/ether.

That is why your numbers are meaningless, unless you know the refractive index of those layers.

In the correct FET, the Sun does set and does rise.

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Offline markjo

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Re: Investigating FE Jupiter
« Reply #17 on: June 06, 2019, 08:50:32 PM »
But it does exist.

Multiple proofs.

GALAEV ETHER DRIFT EXPERIMENTS:
Have any of those experiments measured the index of refraction of aether?
Abandon hope all ye who press enter here.

Science is what happens when preconception meets verification.

Ignorance more frequently begets confidence than does knowledge. -- Charles Darwin

If you can't demonstrate it, then you shouldn't believe it.

Re: Investigating FE Jupiter
« Reply #18 on: June 06, 2019, 09:18:25 PM »
Between Jupiter and the Sun there is a very dense region of aether/ether.

Can you please, care to post further details or evidences about this very dense region?
How do you or someone know that?  How it was measured and verified to sustain such statement?
In case this region is proved to exist, what are the physics that change the angular sizes?  refraction again?
If yes, contrary to what FE Wiki says, light from distance appears bigger, several pictures on wiki sustain it.
If there is no solid bases for such very dense region, then it is just a guessing to justify the numbers, a case when 2+2 = 3 by necessity.
Sandokhan, please, you are affirming statements carrying sure seriously certainty, be prepared to show the test results.
Just for you to know me better and not see me as a keyboard crazy teenager, I am a science teacher and astronomer, optical and radiation engineer at a Florida university.

Re: Investigating FE Jupiter
« Reply #19 on: June 06, 2019, 09:29:49 PM »
Can you please, care to post further details or evidences about this very dense region?
How do you or someone know that?  How it was measured and verified to sustain such statement?


I already have.

KORONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2057945#msg2057945

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2058259#msg2058259

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064256#msg2064256

NEWTONIUM, the lighter than hydrogen element (ether):

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2064764#msg2064764

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg2065771#msg2065771

RUDERFER EXPERIMENT: ABSOLUTE PROOF OF THE EXISTENCE OF ETHER, the first null result in ETHER DRIFT HISTORY

https://www.theflatearthsociety.org/forum/index.php?topic=30499.msg1846721#msg1846721

Here is the true periodic table of the elements published by Mendeleev:



Group 0, line 0: NEWTONIUM

Group 0, line 1: CORONIUM

In 1902, in an attempt at a chemical conception of the ether, he put forward the hypothesis that there are in existence two elements of smaller atomic weight than hydrogen, and that the lighter of these is a chemically inert, exceedingly mobile, all-penetrating and all-pervading gas, which constitutes the “aether.”

"Mendeleev devoted considerable attention to elements occurring before hydrogen in the periodic table. He gave a number of reasons for taking such a possibility seriously: first of all, the discovery of a whole new series of elements, the noble gases, in the closing years of the nineteenth century led him to think that this series could be extended upward to earlier analogues of the first two noble gases, helium and neon. Second, the apparent success of the ether theory in optical physics suggested to him that ether should be identified as a new element, which he chose to call newtonium. Third, ether would have to lack the ability for chemical combination since it was believed to permeate all substances. In addition, the notion of a completely unreactive element had become highly plausible after the discovery of the unreactive noble gases. Mendeleev predicted the existence of two elements lighter than hydrogen, calling them elements x and y, based on numerical relations between atomic weight ratios in a periodic table, which he devised in 1904.