[sandokhan]

The footage included was shot over 3 hours using an 11-inch Celestron NexStar GPS telescope and a Blackmagic Pocket Cinema camera.

In those three hours, Mars has rotated by almost 90 degrees. If Mars rotates a quarter of a circle in 3 hours, then it makes a full rotation in 12 hours. However, the official full rotation time is ~24 hours and 30 minutes.

On GLP there is a discussion on this topic, but they are not aware of the discrepancy of the rotation time in the video.

Either the author of the video filmed for six hours (the video is for visual effects, and has little to do with astrophysics) or something else is going on.

[sandokhan]

https://x.com/astroferg/status/1880672505326960964?t=8zcwcKVpYxfrRVyo7XU8yA&s=19

[flannel jesus]

Looks decidedly less than 90deg to me

[sandokhan]

If we watch the rotation of the NP, it looks like some 90 degrees. Of course, more observations from amateur astronomers are needed.

[flannel jesus]

I don't know what the np is

[sandokhan]

The area around the north pole in the video.

[flannel jesus]

I watched the bit that starts out in the very center. If it was a full 90 degrees, that section should be entirely to the right, but it's not. If I had to guess, I'd say it looks just slightly past 45deg. I could be underestimating and it could be closer to 60

The north pole doesn't look like it has a lot of distinct features to lock on to, so that feels like an especially bad candidate to base judgements off of.

[sandokhan]

The Martian rotation is increasing by 4 milliarcseconds per year squared. That means the Martian day is shortening by a fraction of a millisecond per year.

60 degrees in 3 hours = 480 degrees in 24 hours, a gain of 33% in the rotational speed.

Of course, in FET it is the layers of clouds which are rotating, not the planet itself.

[markjo]

A Martian sol is a Martian solar day.  That is, one rotation relative to the sun.  That does not mean that a Martian sol will be the same as it's rotation relative to the earth, which will no doubt vary depending on the current positions of earth and mars in their respective orbits.

[flannel jesus]

The Martian rotation is increasing by 4 milliarcseconds per year squared. That means the Martian day is shortening by a fraction of a millisecond per year.

60 degrees in 3 hours = 480 degrees in 24 hours, a gain of 33% in the rotational speed.

Of course, in FET it is the layers of clouds which are rotating, not the planet itself.

Right, I was being as generous as possible with my eyeballing if the rotation, I gave a range. I did not say "this is definitely how fast mars is spinning".

You're latching onto a minute detail and thinking this counts as rigorous measurement. It doesn't. This is just silly people on a forum doing silly things. If you are serious, go buy the equipment to film Mars yourself.

[sandokhan]

We don't care about the martian "sol", that's RET. In FET, the Earth îs stationary while Mars rotates with respect to the Earth.

[flannel jesus]

Are you a flat earther?

[sandokhan]

https://web.archive.org/web/20180512121552/https://www.ucl.ac.uk/mathematical-physical-sciences/images/news/Saturn_3D_final6.jpg

Plasma Flux Transfer Events between Saturn and the Sun

A twisted magnetic field structure, previously never seen before at Saturn, has now been detected for the first time ... When the Sun’s magnetic field interacts with the Earth’s magnetic field (the magnetosphere), a complex process occurs called magnetic reconnection which can twist the field into a helical shape. These twisted helically structured magnetic fields are called flux ropes or “flux transfer events” (FTEs) and are observed at Earth and even more commonly at Mercury ...

It is this kind of flux ropes which are the cause of the modification of the rotational speed of Mars. In my opinion it is the start of the reversal of the galactic magnetic field:

https://lweb.cfa.harvard.edu/~reid/bfield.html

This reversal will start in Sagittarius A, and it will affect the silver galactic center (Orion/Gemini):

https://www.e-education.psu.edu/astro801/content/l8_p7.html

https://ascensionglossary.com/images/1/19/Gate_of_Gods144.jpg?20141213053744

[flannel jesus]

That doesn't sound like stuff a flat earther would say.

[markjo]

Here is a link to a time lapse of the 3 hour video on X.  It’s quite obvious that there is less than 90 degrees of rotation.  Probably closer to the 45 degrees that you would expect.
https://x.com/astroferg/status/1880672505326960964?t=8zcwcKVpYxfrRVyo7XU8yA&s=19&mx=2

[AATW]

The Martian rotation is increasing by 4 milliarcseconds per year squared. That means the Martian day is shortening by a fraction of a millisecond per year.

60 degrees in 3 hours = 480 degrees in 24 hours, a gain of 33% in the rotational speed.

Of course, in FET it is the layers of clouds which are rotating, not the planet itself.

I'm interested what would make the layers of clouds rotate in FET if the planet itself is not.
There's a dark band in the northern hemisphere, it goes about a 3rd of the way across the surface in the 3 hours. Which is about 60 degrees.
But one thing to note is that because the earth is rotating you're not looking at Mars from a fixed point, I guess that must have some effect in what we observe.

[flannel jesus]

But one thing to note is that because the earth is rotating you're not looking at Mars from a fixed point, I guess that must have some effect in what we observe.

I think the effect would be immeasurably small (or maybe just on the edge of measurably small). Imagine drawing a line from the observers point on the surface of earth to the center of Mars at 8am, and then draw that line again from the observers point at 8pm. Those two lines will be different, certainly, but the angle distance between them will be miniscule. Less than a percent of a degree I reckon. I don't think our point of view of Mars would change drastically over the course of the day (until of course it's hidden entirely - that's a pretty big change)

[AATW]

But one thing to note is that because the earth is rotating you're not looking at Mars from a fixed point, I guess that must have some effect in what we observe.

I think the effect would be immeasurably small (or maybe just on the edge of measurably small). Imagine drawing a line from the observers point on the surface of earth to the center of Mars at 8am, and then draw that line again from the observers point at 8pm. Those two lines will be different, certainly, but the angle distance between them will be miniscule. Less than a percent of a degree I reckon. I don't think our point of view of Mars would change drastically over the course of the day (until of course it's hidden entirely - that's a pretty big change)

Yes, thinking about it you are correct.
As we discussed in the eclipse thread, this is all a bit complicated. The rotation is a bit quicker than I'd expect but maybe there's something we're not taking in to account.

[sandokhan]

The rotation is a bit quicker than I'd expect but maybe there's something we're not taking in to account.

This is what it is not being taken into account:

https://zetatalk.com/index/sign1083.jpg

https://zetatalk.com/newsletr/issue737.jpg
The 3:18 image captured the Winged Disc, the prior and later images did not have this rare capture. Per Skymap, only the planet Mercury should be in the four o'clock position on that day, to the right of the Sun.

Garuda, video and image:

https://twitter.com/Mixmasterxl/status/1770541769635033444

https://pbs.twimg.com/media/GJngMN3XgAAfQFr?format=jpg&name=medium






In the video there are at least 60 degrees of rotation, the figure might be even higher than that. Even if the angle of rotation would be, let's say, 48 degrees, the phenomenon could not be accounted for (official data: The Martian rotation is increasing by 4 milliarcseconds per year squared. That means the Martian day is shortening by a fraction of a millisecond per year).


The supernova remnant of the Sagittarius A event is the Crab nebula.

The possibility that high-intensity cosmic ray electron fronts could
travel out through the Galaxy from a source at the Galaxy’s center is a new
idea that was inspired by the zodiac’s galactic explosion message.
Consequently, astronomers had not previously seriously considered the
notion that the cosmic ray electrons trapped in these remnants might have
come from interstellar space. They presumed that the cosmic rays are
spread relatively uniformly throughout the Galaxy and have an intensity
about as low as levels currently observed in the vicinity of the solar system.
Of course, such intensities would be far too low to produce the large
quantities of synchrotron radio wave emission seen to come from these
remnants. As an alternative, astronomers speculated that the cosmic rays
producing this emission might have come from the original supernova
explosion. However, this theory failed to account for the radio wave output
from some of the more luminous remnants, such as Cassiopeia A and the
Crab Nebula.

In the case of the Crab Nebula, astronomers have
suggested that the electrons are being supplied by the Crab pulsar, a
pulsating neutron star located near the nebula’s center, or at least along our
line of sight to its center.

However, the cosmic rays producing the radiation seen to come directly
from the pulsar may not necessarily be the only ones energizing the Crab
Nebula. This much may be gathered by comparing the pulsar’s radiation
spectrum to that of the nebula (see figure 10.7). Whereas both spectra have
the same slope in the X-ray frequency region, their radiation intensities
(flux densities) both decreasing with increasing frequency in a similar
fashion, the slopes of the two spectra differ substantially in the radio and
optical spectral regions. Most of the Crab Nebula’s X-ray emission comes
from a localized region lying within half a light-year of the pulsar; hence,
much of it may be powered by the pulsar’s cosmic ray wind.

Interestingly, the radio map of Cassiopeia A presented in figure 10.8 shows the
remnant to be most luminous on its westward side (right side), which faces
the Galactic center and would be receiving the full brunt of the superwave
onslaught. Furthermore, the remnant is seen to be least luminous on its
eastern side (left side), which is in the lee of this cosmic ray wind. A
similarly skewed distribution in brightness is apparent in X-ray images of
Cas A, such as the one shown in figure 10.9.

[flannel jesus]

Absolute crazy person post. Just complete random pictures and videos with no explanation for how they relate to mars rotation.