How do seasons work?
« on: June 14, 2019, 05:12:08 AM »
After reading your FAQ, I understand the general concept you have for how seasons work - that seasons are dependent on how close the sun is to the north pole, and as the sun moves closer and further away from the centre of the disk, the seasons change accordingly.

My question is, what is the mechanic behind this? What explanation do you have for the sun moving closer and further from the centre?

Re: How do seasons work?
« Reply #1 on: June 14, 2019, 04:10:09 PM »
It seems to be some mechanical celestial gears. 

But you forgot to think about the Sun's circling speed. 

To complete a full 24 hours turn over the FE, the angular speed will be the same, 15° per hour, but its speed must be faster when distant from the North Pole due larger circling diameter.  It means, it would run faster overhead people in Rio de Janeiro in December, than it would do in June over people in New York. 

Due this higher speed over southern hemisphere in December, It would pour less radiation per km²/second than on northern hemisphere in June.  Even if you can consider the Sun being lower altitude on December to compensate the less radiation per km², there is the exposure time difference, impossible to compensate.  As it travel faster, its visible time on sky would be smaller, people on the southern hemisphere in December would have a very shorter daylight than northern hemisphere on June, what it is not true.

Other than that, if the Sun is lower altitude in December, an observer over Equator at noon time would see the Sun lower at the south, compared of what he can see at noon time on June, sun at the north.  That is not true at all.  Both people, Rio or New York see the same Sun apparent size, 0.5°.   Also, with the Sun being at different altitudes would produce a different sizes of shadows of a same pole vertical in the ground at 2pm, June on Cancer, December on Capricorn.  On RE world, the shadows would have the same length, June on Cancer = December on Capricorn, and also, June of Capricorn = December on Cancer.    Also, the changes on the shadow size in one hour, would be the same on both tropics on RE, that will be not true on FE.

FEs say you can not see far, light bends, Sun appears to be low on horizon (sunrise & sunset) due refraction when it still high in sky, but mostly because atmosphere not be transparent.  This effect should happen all over FE, so the Sun would disappear due atmospheric refraction no matter the hemisphere.  People in Rio de Janeiro would see the sun rise at 10am and set at 4pm on summer time, December, that is totally nonsense, not true.  Summer in Rio shows almost 13~14 hours of Sunlight.

Because I have a calculator and know how to use it, I already posted all this distances, calculations, numbers based on FE, on another post, as usual not a single blip from FE scientists on this radar. 

FE Tropic of Capricorn circumference: 79191km, Sun's speed: 3300 km/h.
FE Tropic of Cancer circumference: 46471km, Sun's speed: 1936 km/h

See: https://forum.tfes.org/index.php?topic=14844.msg193713#msg193713 post #40.
« Last Edit: June 14, 2019, 04:27:22 PM by spherical »

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Re: How do seasons work?
« Reply #2 on: June 14, 2019, 08:31:07 PM »
...
about the Sun's circling speed. 
...
See: https://forum.tfes.org/index.php?topic=14844.msg193713#msg193713 post #40.

In addition to your link:

Quote

We know that Sun travels 15 degrees per hour, measured from observer from any place, any time of a day.
...
Distance from North Pole to Tropic of Cancer is measured to be 7389 km.
It gives the circumference of 46 426 km, which Sun travels in 24 hours on summer solstice.
It is 1934 km per hour, 967 km in 30 min.
For Summer Solstice:
standing at Tropic of Cancer at solar noon you have Sun above your head, and 30 min later Sun is 7.5 degrees and 967 km to the west.
This gives Sun's altitude of 967 / tan(7.5) = 7345 km.

Distance from North Pole to Tropic of Capricorn is measured to be 12 611 km.
It gives the circumference of 79 237 km, which Sun travels in 24 hours on winter solstice.
It is 3302 km per hour, 1651 km in 30 min.
For Winter Solstice:
standing at Tropic of Capricorn at solar noon you have Sun above your head, and 30 min later Sun is 7.5 degrees and 1651 km to the west.
This gives Sun's altitude of 1651 / tan(7.5) = 12541 km.

One factor why the part south of equator would receive less energy per day is faster Sun over the same area.
Another reeason is the height above the ground. When Sun is 1.7 times higher, the ground already receives 1.72 = 2.89 times less energy.
It is only 34.6% in December of what north receives in June.

This thing alone should make average temperature of the south to be around 220 Kelvin (-63 F, -52.5 C), instead of current 286.5 K (56 F, 13.3 C).
Maybe even lower.