Metatron, if I understand correctly, you are standing at the center of FE holding one end of a chain with a "large steel ball" attched at the edge of FE and you expect that if FE is rotating (never heard a FE theory where FE rotates around the center - the sun and moon always move), the chain will not have tension because it is moving slowly? That chain is 8000 miles long and has its own effect on the physics, but let's assume it is weightless. I need to know the exact situation with the ball, its mass and is it lying on the surface, coefficient of friction.

I suggest you forget the chain. In general, a ball at the edge of a spinning disk has angular velocity. If the ball is heavy and the spinning is slow, it just sits there. For 8000 mi radius disk spinning at 1 rev/day, the speed at the equator is 1000 mph, much more at the edge, too lazy to calculate, but 1000 mph is enough. So we have a presumably heavy ball traveling at 1000+ mph at the edge of a disk. That ball will travel straight at any given instant, but the path is curved, so some force must be applied towards the center or it flies off the disk. At 1000+ mph with a heavy ball, gonna be a lot of force.

Another way to look at it is suppose you have a ball traveling at 1000 mph on the end of a chain you are holding. Will the chain just lay on the ground? No. If the chain is 100 ft long and 1 rev/day, not much force. If the ball is traveling at 1000+ mph, huge force.

In general, your thought experiment is meaningless until you put numbers to it. You can imagine the results any way you like, perhaps you like an interpretation that fits with your FE beliefs. Real calculations with observed numbers and Newton's laws are consistent with RE