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Flat Earth Theory / Re: Ships, Their Movements on the Horizon, and Navigation by Star Constellations
« on: March 10, 2017, 11:19:35 PM »Water is pulled toward the spherical surface towards what? The center of the Earth?A drop of water isn't what I was referring to. I was referring to waters propensity to find its own level.
The water droplets show that the shape is determined by the forces acting on it. For a small drop of water, surface tension causes it to form into a small sphere. On the large scale, water is pulled towards the spherical surface of the earth due to gravity. There is no "finds its own level law" that would prevent water from naturally forming into a spherical shape.
Approximately, yes.
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Does most of the mass on Earth exist in the exact diametric center of it?
No. http://hyperphysics.phy-astr.gsu.edu/hbase/Mechanics/sphshell.html#wtls
Edit: Or from wikipedia, if you prefer: https://en.wikipedia.org/wiki/Shell_theorem
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Is it just the perfect amount of mass to counter the centripetal force of our spinning planet to keep the water and atmosphere from flying into outer space?
No. Gravity is much stronger than centripetal acceleration. It isn't balanced at all. This is why we fall down towards the earth, and aren't thrown off.
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If you're only explanation is Gravity, which is not without its detractors in main stream science, then it's not enough. It's convenient, but can not be measured, for many of the same reasons the movement of the Earth can't be measured. This is the high burden of proof I was talking about before.
You have no earthly idea what you are talking about.
https://en.wikipedia.org/wiki/Gravimetry
https://en.wikipedia.org/wiki/Tests_of_general_relativity
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QuoteQuoteThe vanishing point is the place where level horizontal lines converge.
Equations please. You just said that "estimating the distance to the horizon is still possible on a flat earth". An example would be nice, with actual numbers and equations.
You could use the same equation they use now, except instead of explaining the coefficients with curvature, it could easily be attributed to the perceived rise of the ground to meet the sky due to the laws of perspective.
Please show how those equations correspond with your theory about the vanishing point. Those equations were derived directly from the geometry of a spherical earth. They are not general purpose, best-fit equations. I have derived them from scratch myself on this very forum.