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Messages - Mock

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1
Basically, I wanted to draw some attention to this:
(I figured this might merit its own topic, since it's more of a theoretical question and doesn't have anything to do with high altitude balloon videos)

The question the FE'ers don't like you to ask is how the moon is lit by the beam of spotlight sun at night...and if it isn't, how the hell are there phases of the moon?
The sun has two beams of light?

Well - it needs another one to cast light on Venus, and another on Mercury, and...well, one for every planet, moon, asteroid and comet that shows "phases" when viewed through a telescope.

In the "unipolar" map - the beam that lights up the Earth would have to be semi-circular in order to light up just the half of the world that is in daylight.

In the "bipolar" map - the beam would have to have little curved tails and change shape continually through the day and through the year in order to track the weird shapes of the lines of longitude.  The data from solar panel plants on PVoutput.org clearly demonstrates how that shape must be changing.

Can the Flat Earth Society explain why the Sun, as postulated by both FE models, only illuminates part of the Earth, while at the same time illuminating other objects, such as the Moon (which is definitely being illuminated)?

2
Flat Earth Theory / Re: Disproof: Neither map explains the equinox.
« on: November 13, 2017, 12:06:24 AM »
Just really quick, since I should be sleeping and don't have much time:

I think that if someone could visualize the positions and power outputs on a map with a Lat/Long grid, it might clear up the argument a bit. I might have time to do it tomorrow (European) night, but if anyone else feels like it in the meantime, feel free.

And douglips, you really are a genius for coming up with the solar cell thing :>

3
I would love for Tom Bishop to respond to my response to him!
Oh sweet summer child ...
We would all love it if FE'ers actually engaged in proper discussions with us. Sadly, that's not what usually happens :(

4
Flat Earth Theory / Re: Pinhole cameras, Sunsets and FET perspective.
« on: August 23, 2017, 04:15:31 PM »
I'm really liking these 3DGeek, and not just because they are excellent proofs, but I'm learning more precise details about the world around me from your posts which is awesome! This for example. I knew there was something fundamentally wrong with what Tom was trying to say, but I never would have thought to lay it out like this as I didn't know about pinhole cameras. Thank you for all the work you've been putting in here and in the other threads, even if Tom's head seems tougher to break through than Wolverine's. Even if he never ever admits a thing, these threads have been very interesting and educational for me and I hope others, so thank you.
I agree 100%. Thanks for making discussions here worthwhile (and even educational) for a change and keep up the great work :)

5
Since Tom probably won't bother to reply anyway (as he always does when he gets stuck), let me save you some waiting time.

"You'll have to prove those maps are not based on RE latitudes and longitudes or using other RE assumptions"

6
What if the solar eclipse is a part of a sun hologram, and the sun is definitely an interactive hologram!
What if we're all floating unconscious in a giant jar of magical peanut butter along with unicorns and leprechauns with 3.1415 fingers on each hand, and they're manipulating our brains Matrix-style using fairy dust and reptilian magic to make us experience the things we do, AND make annular solar eclipses possible?

Everyone can write up some bullshit that is impossible to directly disprove. It will still be bullshit, though.
And that's disregarding the fact that my bullshit is still even harder to disprove than yours...

7
Flat Earth Theory / Re: Distance debate based on poll results
« on: August 23, 2017, 09:57:54 AM »
Since this is all "known" and "proven" (your words), please provide this proof. Provide evidence that:

- GPS predicted distances are accurate
- Round Earth Latitude and Longitude are accurate
- Aircraft cruise speeds are measured in a way that does not use a Round Earth coordinate system

If you are making any of these claims, it is your burden to back up your argument and demonstrate it.

The evidence for TomInAustin's 1st claim is a logical argument. If GPS predicted distances are not accurate, then how can it be that GPS-based navigational systems work for millions of people on a daily basis? Are you asserting that they don't work? Or that they do work, but are somehow still not accurate? I really don't know what you're getting at with this. His first claim is definitely valid.

Actually, his second claim has nothing to do with what you are asking us to prove. It is true that aircraft flight times are recorded daily. You can check them out online - just google it. We can assume they are true because, even disregarding the fact that here, too, millions of people experience those flight times daily, how could airlines not know how long their flights take? They have schedules, and if the times were actually inaccurate, there would be delays on literally every flight. Are you going to assert that this is the case? Or are you claiming that even if airlines don't know their own flight times, they somehow still manage to plan everything and be on time in most cases? His second claim, too, is absolutely correct.

And then there's the thing with the cruise speeds. See, you've had 3DGeek, who happens to be a professional and an expert on the topic, explain to you exactly how it is measured and why it is measured as it is in the other thread. I'm sure you remember it - unless you decided to ignore it and walk away from the thread as soon as you started losing, just like you did on my last thread about the magnetic field - TWICE, I might say.

As a matter of fact, 3DGeek also stated why even if cruise speeds are extremely far off, it doesn't matter at all. I'm just going to quote him:
So his ONLY remaining straw to clutch at - his lifeline - is that the speeds that are claimed for these aircraft are wildly incorrect.

BUT - the coup-de-grace is this:  If the speed for the 747 is wildly different than the manufacturers (pilots, control towers, airlines) claim - then IT DOESN'T MATTER!!!   If all of the 747's are 50% faster - then all of the distances we have are incorrect by the same ratio.   AND THAT DOESN'T CHANGE THE FACT THAT THE INTERNAL ANGLES OF THE QUADRILATERALS DON'T ADD UP.
Which brings us to the conclusion that the first claim ("1. GPS is a proven technology that in some cases,  is accurate to centimeters and at worst 10 to 15 meters") is true, the second claim ("2. Flight times between destinations are recorded daily [and are accurate enough]") is also true, and the third claim ("3. Aircraft cruise speeds are known and are filed with flight plans") doesn't even need to be true in order for TomInAustin's question being a valid one. See, there's no point in having a designated week for discussing a specific topic if all you're going to do is deny stuff a schoolboy can prove within ten minutes.

Now, would you please be kind enough as to answer the question this whole thread is about, instead of dodging it like a coward who has no arguments left except for "boo hoo we don't know the distance from NY to Paris, and what's more, you'll NEVER EVER EVER be able to find out heheh!!!!!"
Quote
Here is my first question.  Using the following airline data, how could a flat map possibly allow these numbers?

Origin         Dest                   Miles
Sydney         Santiago           7125
Santiago         Johannesburg   5724
Johannesburg  Sydney      6909

8
Flat Earth Theory / Re: Why space launches?
« on: August 20, 2017, 09:33:21 PM »
*something something infernal astral CIA awakened shapeshifter reptilians*
Umm. Okay.
Do you have any conclusive evidence for that?

9
Under the Round Earth model East does not always point East (except at the equator), and Eastwards navigation is possible. Consider where "East" would point 20 feet from the point of Magnetic North in RET. Why must we believe that North always points North?
The needle in a compass is magnetized, as I'm sure you know. North always points North because of magnetic attraction. I'm not sure I understand what this has to do with East?

10
You can't compare North and South to West and East in this case. North and South always point towards distinct locations, while West and East just go in a direction perpendicular toward the direction of North and South.

Going East until you reach the point you started from again (i.e. one full circle around the Earth), a compass will always show you're going East. Conversely, you can't make a full circle around the Earth by just going North. At some point, your compass needle will spin around and then you'll be going South.


To point to my rough sketch of the bipolar model's magnetic field (which, for the protocol, you have taken no issue with as of now), imagine standing at the position of the far right compass symbol, straight behind the North Pole (but a fair distance away from it). Your compass needle's tip (indicating North) will obviously point at the North Pole, but what about the other directions?

Say you're facing the North Pole. Obviously, North is right in front of you. What about South? Your compass will display South as right behind you - but the magnetic South Pole will, too, be located in the direction you're facing, which is a contradiction.
Imagine going "South" (as read from a compass) from this position - instead of getting closer to the Southern Hemiplane, you would actually be increasing your distance from it. To get to, say, South Africa, you would actually have to travel further North at first.

That's not all, though. If North is straight ahead of you, then East will naturally be to your right and West to your left. Now imagine someone with a compass in the UK, also facing the North Pole. For them, North is also straight ahead, so East will be to their right and West to their left. Since those two observers are looking in opposite directions (facing each other, with the North Pole between them), they can't both be right, though. In this scenario, the Western Hemiplane would become the Eastern Hemiplane after passing the North Pole.

You seem to think that those discrepancies are not observed because one would turn to the right direction while travelling due to curvature of the magnetic field lines. This might be possible for lower longitudes (e.g. travelling from the US to Brazil), where the curvature is not as noticeable and you might not be able to detect the slight shift in direction over the huge distance. But surely a 180 degree turn that is necessary in this case would be noticed? Travelling South, I'm confident you would notice that you are now facing stars that were behind you earlier during the journey.

So by claiming the Bipolar Model can be valid, you are either asserting that
  • a standard magnetized needle compass with N and S at a 180° angle displays a wildly incorrect direction for South when facing the North Pole from the side opposite Western Europe
  • there are locations on the far side of the poles where the directions of West and East as displayed by a standard magnetized needle compass are inversed, i.e. the shortest way from Berlin to Moscow is to go West
or you are asserting that travelling South from the far side of the North Pole will result in a gradual 180 degree turn that is somehow not noticed despite the existence of navigational devices other than compasses.

While those are really outlandish things to say, if they are actually true they shouldn't be hard to prove at all.

11
The evidence for your assertion was that it was "common knowledge". I just assumed that you had no further intellectual stimulation to contribute towards the topic.

I've made this clear multiple times now, and I will once more: This is not the case. My two posts and the rather long PM you chose to ignore might have tipped you off. I'm not the one who stopped contributing for a week because of a minor detail. I'm sorry if said minor detail offended you, but had you read the rest of what I wrote and not just those three words, I'm sure that would have saved us lots of drama. The evidence for my assertion was not that it was common knowledge. The evidence was everything I said in the rest of the post, which you decided to disregard.

I've made my point on the topic:

It's common knowledge. Since I assume you don't have a compass handy, unlock your iPhone. Open the Compass app. You'll notice it works just like a real one. You'll also notice that "N" for north is at a 180 degree angle to "S" for south, and they don't change positions. This means that at any given position, if you face North and turn 180 degrees you'll face South. This is clearly not the case in the bipolar FE model, as I have illustrated:

At the position on the left, you actually get a very acute angle from North to South and certainly not 180 degrees. Ask yourself: What direction is West? To assert that the BP model is correct would be to assert there are points on Earth that inherently give inaccurate compass readings because of their position in the geomagnetic field (excluding the Poles, but that should be really obvious). The burden of proof is on you.

Since you seem to be willing to engage in the discussion again (which I am thankful for), by all means go ahead. I'm all ears.

12
I sent him a PM explaining in detail what I meant by "common knowledge". He's ignored it so far, yet he has obviously been online and active since I sent it almost a week ago. I guess that proves my point? ::)

Hello. To get straight to the point:
It's common knowledge.

I see. Then I suppose that we have nothing further to discuss, since truth is based on popular authority.
I think this is a very bizarre and, to be honest, also an unfair reaction. I made the effort to answer your question with a detailed explanation based on common knowledge (the common knowledge in this case being nothing more than "on a compass, the angle between North and South is 180 degrees, and the two ends of the needle simultaneously point north and south, respectively"). You then proceeded to dismiss my explanation, ignore the rest of the post and leave the thread just because my response is founded on common knowledge. Not all of it is automatically wrong, you know ("the sea is filled with saltwater" is common knowledge and a proven fact), and I NEVER asserted that truth is based on popular authority. That's just you being dishonest and looking for a way out.

[It can be observed that on a normal compass with a magnetized needle, whenever one end points towards the North Pole, the other points towards the South Pole and vice versa.

Who observed that?
I answered your question. Since you're not disputing my claim, until you give a proper answer I'll just assume you acknowledged that I'm right and gave up, and that you're not responding in order to save some face.

13
Flat Earth Theory / Re: What about World's End?
« on: August 12, 2017, 09:39:19 PM »
Actually, I take back my statement about you being pleasant to discuss with.
Well that hurt my heart a little.

All I wanted was for you to acknowledge that not everything in Round Earth Theory was straight forward and easy to explain, and that some things are incorrect ... such as full moons. So that you wouldn't hold me to account on every little semantic point, when you don't hold your own beliefs to such scrutiny. You probably never even considered that a full moon is impossible on a round earth, yet you have known about them all your life. And yet 5 mins into Flat Earth theory, you are trying to tear it to bits looking for any tiny flaw in explanation.

Some things you should always consider when asking flat earthers questions ... we don't have a flat earth google, we don't have the weight of the world's scientists to lean on, and we don't know every last piece of physics of the universe any more than round earth scientists do. Regular scientists can't explain gravitons. They can't even isolate them. But yet a flat earther needs to prove in minutia the concepts of universal acceleration. This isn't a forum run by God and His angels. Just people who question what they are told. I'd always rather be one of those people.

Any time the moon is within a few degrees or less of passing into the shadow to create a lunar eclipse is a full moon. You need to look at it from more than a single angle.
In a round earth 'full moon', the moon is said to be 5 degrees off the ecliptic. The very notion that it is a ball and 5 degrees off, means there is no way you could ever view the full shining face of the moon and still be stood on earth. Ergo, there is no such thing as a full moon.
Sorry about hurting your heart. You just effectively restated what I said. You are right, there is no such thing as a full moon - full as in 100% illuminated when observed from Earth. This article should answer all your questions about this. If not, I'll gladly answer them and listen to your explanation as to why the explanation given in the article is not valued. (there seems to be a displaying / typing error on that site that makes all the apostrophs appear as question marks)

You have yet to produce any explanation for how the moon can possibly appear full on a Flat Earth. I'm waiting.

14
Thanks for answering. I get why calculating the angles is a good idea, but what do you mean when you say I should calculate the other distances? This is one possible FE layout of many. In this specific one, all the distances are known already. I could make another one (either by tweaking other distances than NY-CT and BA-PA, or by calculating the angle in another corner), but I don't understand how that would help disprove FE theory.

We're having house guests from tomorrow until next weekend, but I'll see if I can find the time to do all the math. If anyone else wants to do it in the meantime, you're welcome to post it here.

15
Flat Earth Theory / Re: What about World's End?
« on: August 12, 2017, 05:18:49 PM »
So being as you both say earth and the moon are balls, you are both saying there is no such thing as a full moon. Well there are full moons. My calendar says there are 13 of them this year. So my point, saying the earth is round has a whole bunch of problems that a flat earth doesn't.

https://www.timeanddate.com/moon/phases/
There it is. A mathematical calculator using mathematics to tell you when the next full moon occurs. Not the next almost full moon. The next full moon ... which is impossible on a round earth because for the moon to be full, the sun has to be directly behind the earth, and that causes a lunar eclipse instead.
Actually, I take back my statement about you being pleasant to discuss with. It's called a Full Moon because it looks full - you won't be able to tell it's not just from looking at it. It's as full as it will get. We still don't get to see 100% of the illuminated side ever, because obviously it would result in a lunar eclipse.

And the FE model has WAY more problems with moon phases than the RE one - the generally accepted one, I might say - has. Explain to me, how can you see a 100% full moon in your model?

16
Flat Earth Theory / Re: Airline flight data - summary.
« on: August 12, 2017, 10:47:21 AM »
Quote
This won't work for the simple fact Tom claims (in effect) that we can't know the true distance between any two points unless we've personally walked the distance with a measure of some kind. That's why he said we don't know the distance from New York to Paris.
Yeah, I got that. My proposed method is:

1. Find any reasonable distances between the four places used in the proof that would work for a Flat Earth.
2. Then calculate the speed at which planes would have to go to travel those distances and be on schedule.
3. See which ones are way too fast, which ones are way too slow and adjust your distances - again so that a FE is possible.
4. Repeat 2 and 3 multiple times.

I think that at some point, we will have reached some kind of equilibrium, where the values for the distances are as accurate as they can get, assuming the cities they connect are located on a Flat Earth. If the times, velocities and distances match up, then we have proof that a Flat Earth is possible. If they don't, we'll have proof it isn't.

I hope I was able to formulate it a bit better this time :)

EDIT: Could someone please just tell me real quick if it will work? I really want to go to sleep right now, it's 3:06 AM
If you keep the ratios between them the same you will never have the angles work. You would need to drastically adjust the ratios of the distances in order to be able to create a flat pair of triangles that would be able to work in the way the picture says they should.

I made a post about this :) Could you explain over there what you mean by keeping the ratios the same?

17
So, TFES' counter-argument for the Quadrilateral Proof is that we don't know if the distances are correct. All right.
What if we prove that for any FE map configuration that does get the angles right by using other distances, therefore avoiding the proof, those other distances will still not match up with the flight times and speeds?

If the Earth is flat, there MUST be a constellation where BOTH

1.   The Quadrilateral Proof gives identical angles
2.   The times that it would take planes to fly the distances matches those given by airlines like Qantas, calculatable by dividing the distances by the cruise speed of the planes used / Alternatively: The cruising speed the plane would need to have in order to complete its journey in the given time matches the one that is given for each plane type and flight
3.   (optional) The angles between the cities would have to remain roughly the same (not sure, since FET seems to question those angles anyway)

If there is no such constellation, then the Earth cannot be flat. Shouldn't be too hard.

I will be using http://www.calculator.net/triangle-calculator.html for the angles.
Flight distances will be taken from WorldAtlas (all in km). The corner points are New York (NY), Paris (PA), Buenos Aires (BA) and Cape Town (CT).

NY - PA 5919
NY - BA 8383
NY - CT 12472
CT - PA 9148
CT - BA 6938
BA - PA 10930

Result for angle at NY calculated directly: 98.201°
Result for angle at NY calculated by adding: 31.814° + 43.611° = 76° => Difference of ~22°

Okay, so as we all can see, with the data we get from WorldAtlas, Earth cannot be flat. So let’s just change those numbers up a bit. At this point I’m not sure yet, but I think in order for the second angle to get closer to the first one, we’ll have to make NY – CT and BA – PA a bit shorter. Shall we? Let's say NY – CT 10000; BA – PA 8000, the other distance figures stay the same.
Result for angle at NY calculated directly: 65.401°
Result for angle at NY calculated by adding:  43.24° + 64.294° = 108° => Difference of ~43° in the other direction

Okay, seems like I went a little bit overboard, but the angles did go into the direction I wanted them to. We can change the relevant angles by changing those two distances. Let’s try NY – CT 11000 and BA – PA 9500. The rest stays the same.
Result for angle at NY calculated directly: 81.272°
Result for angle at NY calculated by adding: 56.248 + 39.092° = 95°

We’re getting closer to distances that would work on a FE, but NY – CT and PA – BA still seem to be a little too short. Considering the huge effect it had before, let’s just add 500 km to each figure. NY – CT 11500 and BA – PA 10000.
Result for angle at NY calculated directly: 86.993°
Result for angle at NY calculated by adding: 36.8° + 52.115° = 88.915°

We’re getting really close now – so close that the digits after the dot will soon get important, so I stopped rounding the sums out of laziness. Our added angle is two degrees greater than the first one. I’m going to add a smaller bit of length: NY – CT 11550 and BA – PA 10050.
Result for angle at NY calculated directly: 87.513°
Result for angle at NY calculated by adding: 36.561° +  51.695° = 88.256°

The two angles are now less than a degree apart – a mere 0.743°. I’ll try adding just 30 km more to both distances. NY – CT 11580 and BA – PA 10080.
Result for angle at NY calculated directly: 87.862°
Result for angle at NY calculated directly: 36.417° +  51.442° = 87.859°

(I have proof for those angles and distances - 87.862°, 36.417° and 51.442°)

As you can see, the difference between the angle calculated from NY – PA, NY – BA and BA – PA is now only 0.003 degrees smaller than the one added up using the other distances. If the distances were like this in the real world, then mathematically the world could be flat.

Summing the first part up, our distances could be:

NY - PA 5919
NY - BA 8383
NY - CT 11580 – now 892 km less than before
CT - PA 9148
CT - BA 6938
BA - PA 10080 – now 850 km less than before

Note that we could also have done this by increasing the other distances, instead of decreasing those two – or a combination of both, which would probably give more accurate results, but I don’t think it matters. If anyone wants to put in the extra work (I’m looking at you, Flat Earthers – this might actually be a method to create a more or less accurate flat map!), you’re very much welcome to do that. I'll edit my post accordingly.

Now, before I start calculating with the flight times and velocities of the planes, does anyone have objections to how I'm doing this? Because I don’t want to do all that work without making sure it doesn’t get discredited again.

18
It's common knowledge.

I see. Then I suppose that we have nothing further to discuss, since truth is based on popular authority.
Come on, you just ignored everything else to focus on those three words instead? We have plenty to discuss. Just read the rest of the post and don't run away from the discussion because I assumed you know what a compass looks like and how it works. Excuse me, but that is common knowledge.

19
Flat Earth Theory / Re: Airline flight data - summary.
« on: August 12, 2017, 12:56:37 AM »
Quote
This won't work for the simple fact Tom claims (in effect) that we can't know the true distance between any two points unless we've personally walked the distance with a measure of some kind. That's why he said we don't know the distance from New York to Paris.
Yeah, I got that. My proposed method is:

1. Find any reasonable distances between the four places used in the proof that would work for a Flat Earth.
2. Then calculate the speed at which planes would have to go to travel those distances and be on schedule.
3. See which ones are way too fast, which ones are way too slow and adjust your distances - again so that a FE is possible.
4. Repeat 2 and 3 multiple times.

I think that at some point, we will have reached some kind of equilibrium, where the values for the distances are as accurate as they can get, assuming the cities they connect are located on a Flat Earth. If the times, velocities and distances match up, then we have proof that a Flat Earth is possible. If they don't, we'll have proof it isn't.

I hope I was able to formulate it a bit better this time :)

EDIT: Could someone please just tell me real quick if it will work? I really want to go to sleep right now, it's 3:06 AM

20
It's common knowledge. Since I assume you don't have a compass handy, unlock your iPhone. Open the Compass app. You'll notice it works just like a real one. You'll also notice that "N" for north is at a 180 degree angle to "S" for south, and they don't change positions. This means that at any given position, if you face North and turn 180 degrees you'll face South. This is clearly not the case in the bipolar FE model, as I have illustrated:

At the position on the left, you actually get a very acute angle from North to South and certainly not 180 degrees. Ask yourself: What direction is West? To assert that the BP model is correct would be to assert there are points on Earth that inherently give inaccurate compass readings because of their position in the geomagnetic field (excluding the Poles, but that should be really obvious). The burden of proof is on you.

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